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6x^2-240=-18x
We move all terms to the left:
6x^2-240-(-18x)=0
We get rid of parentheses
6x^2+18x-240=0
a = 6; b = 18; c = -240;
Δ = b2-4ac
Δ = 182-4·6·(-240)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-78}{2*6}=\frac{-96}{12} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+78}{2*6}=\frac{60}{12} =5 $
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